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 tan (AB) = (x (2x1)x1)/ (x1)* (2x1)x Value of both numerator and denominator on RHS are equal hence, tan (AB) = 1 or AB = 45 HOPE THIS ANSWER WILLCalculus Evaluate limit as x approaches 0 of (tan (2x))/x lim x→0 tan (2x) x lim x → 0 ⁡ tan ( 2 x) x Evaluate the limit of the numerator and the limit of the denominator Tap for more steps Take the limit of the numerator and the limit of the denominatorFind the binomial expansion of (48x)^(3/2) in ascending powers of x, up to and including the term in x^3 Give each coefficient as a fraction in its simplest form

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Tan 2x is equal to-64 Equation of a tangent to a curve (EMCH8) At a given point on a curve, the gradient of the curve is equal to the gradient of the tangent to the curve The derivative (or gradient function) describes the gradient of a curve at any point on the curve Similarly, it also describes the gradient of a tangent to a curve at any point on the curve Check the below NCERT MCQ Questions for Class 12 Maths Chapter 7 Integrals with Answers Pdf free download MCQ Questions for Class 12 Maths with Answers were prepared based on the latest exam pattern We have provided Integrals Class 12 Maths MCQs Questions with Answers to help students understand the concept very well

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(x) are non constant continuous and differentiable functions and f(x) is a polynomial of degree 4 with leading coefficient equal to 1, then for at (A) Area of the smaller region bounded by the curve y = f(x)and xº y = 1 is T 2 squnits 4 5 (B) Area included between y = f(x);y 2 = 0 and between ordinates x = 0 and x = 3 is 33 squnits 5 3 Area bounded by the line y = x 1 and y = f(x Misc 15 sin(tan−1 x), 𝑥 < 1 is equal to (A) 𝑥/√(1 − 𝑥2) (B) 1/√(1 − 𝑥2) 1/√(1 𝑥2) (D) 𝑥/√(1 𝑥2) Let a = tan−1 x tan a = x We need to find sin a For this first we calculate sec a and cos a We know that sec2 a = 1 tan2 a sec a = √(1𝑡𝑎𝑛2 a) We convert t lim_(x to 0)(x)/(tan^(1)2x) is equal to Updated On To keep watching this video solution for FREE, Download our App Join the 2 Crores Student community now!

Given, tan(cotx) = cot(tanx)= tan(2π −tanx) ⇒ cotx =nπ 2π −tanxThe hyperbolic functions represent an expansion of trigonometry beyond the circular functionsBoth types depend on an argument, either circular angle or hyperbolic angle Since the area of a circular sector with radius r and angle u (in radians) is r 2 u/2, it will be equal to u when r = √ 2In the diagram, such a circle is tangent to the hyperbola xy = 1 at (1,1)If tan 1 2x tan 1 3x = π / 4, then x = If tan 1 2x tan 1 3x = π / 4, then x = 1) 1 2) 1 / 6 3) 1, 1 / 6

Lim x→0 ex (e tanxx 1) / (tan x x) this is nothing but the standard limit limit x tends to 0 (e x 1)/x = 1 where x = tanx x so it is equal to 1 so the answer is 1 and not 1/2 we can also check this by L hospital rule as it is 0/0 We are all IITians and here to help you in your IIT JEE preparation 70k views asked in Class XII Maths by nikita74 (1,017 points) If x≤ 1, then 2 tan 1 x sin 1 2x/1x 2 is equal to (a) 4 tan1 x (b) 0 (c) π/2$\frac {\sin (2x)} {\cos x}=\frac {2 \cos (x) \sin (x)} {\cos x}=2\sin x$ Thus, the derivative of your left hand side is also the derivative of $2 \sin x$, which is $2 \cos x$ As a side note, this is a specific case of a general rule It's often better to simplify the function BEFORE taking the derivative, as it leads to easier, equivalent answers

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Tan 5x tan 3x tan 2x is equal to????Explain how this sum can be solvedTan 5x= tan (3x2x)Tan5x= tan3x tan2x/1tan3xtan2xTan5x tan 2xtan3xtan5x = tan 3xBITSAT 16 If tan ( cot x) = cot ( tan x), then sin 2x is equal to (A) (2/(2n1)π) (B) (4/(2n1)π) (2/n(n1)π) (D) (4/n(n1)π) ChRD Sharma solutions for Class 11 Mathematics Textbook chapter 9 (Values of Trigonometric function at multiples and submultiples of an angle) include all questions with solution and detail explanation This will clear students doubts about any question and improve application skills while preparing for board exams The detailed, stepbystep solutions will help you understand the

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 If tan x = t then tan 2x sec 2x is equal to A \(\frac{1 t}{1 t}\) B \(\frac{1 t}{1 t}\) C \(\frac{2t}{1 t}\) D \(\frac{2t}{1 t}\) 1) Find sin 2x, cos 2x, and tan 2x from the given information tan x = − 1/6, cos x > 0 sin 2x = cos 2x = tan 2x = Precalculus I am trying to submit this homework in but i guess i'm not doing it in exact values because it is not accepting itPractice Example for tan 2 theta Question Find tan 2 x, if tan x = 5 Solution = = = 10 ⁄ 24 = 5 ⁄ 12 (Simplify it) To check other mathematical formulas and examples, visit BYJU'S

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IIT JEE 1999 limx → 0 ( x tan 2x 2x tan x/ (1 cos 2x)2) is (A) 2 (B) 2 (1/2) (D) (1/2) Check Answer and Solution for above The expression (tan^4x2tan^2x1)cos^2x ,w h e nx=pi/(12), can be equal to (a) 4(2sqrt(3)) (b) 4(sqrt(2)1) (c) 16cos^2pi/(12) (d) 16sin^2pi/(12) Updated On 86 To keep watching this video solution for The value of is option 2) Stepbystep explanation We have, To find, the value of ∴ Using identity, ∵ Using trigonometric identity, Hence, the value of is option 2)

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Watch Video in App This browser does not support the video element 0 k 10 k Answer The Second Derivative Of sec^2x To calculate the second derivative of a function, differentiate the first derivative From above, we found that the first derivative of sec^2x = 2sec 2 (x)tan(x) So to find the second derivative of sec^2x, we need to differentiate 2sec 2 (x)tan(x) We can use the product and chain rules, and then simplify to find the derivative of 2sec 2 (x)tan(x) is Check the below NCERT MCQ Questions for Class 11 Maths Chapter 2 Relations and Functions with Answers Pdf free download MCQ Questions for Class 11 Maths with Answers were prepared based on the latest exam pattern We have provided Relations and Functions Class 11 Maths MCQs Questions with Answers to help students understand the concept very well

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 Given tan x = \(\frac{a}{b}\) The value of the expression b cos 2x a sin 2x Now consider b cos 2x a sin 2x`int tan(xalpha)tan(xalpha)tan 2x dx` is equal to About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How works Test new features © I understand the trig function involved if it's just (2x) and tan is not squared @Tyrion101, despite what others have said in this thread, yes, tan 2 ⁡ ( 2 x) is the square of tan ⁡ ( 2 x) Tyrion101 said But is it equal to (2tanx/1tan^2x)^2 is what I'm asking I

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Also, Sin 2x = $\frac{2tanx}{1\tan 2x}$ To Prove Sin2x in the form of tanx x which is equal to $\frac{2tanx}{1\tan 2x}$ Now let us start the proof from the righthand side and hence, prove it as LHS = RHS RHS = $\frac{2tanx}{1\tan 2x}$ ⇒ 2$\frac{sinx}{cosx}$ / Sec²x ⇒ 2$\frac{sinx}{cosx}$ / $\frac{1}{\cos 2x}$In mathematics, the trigonometric functions (also called circular functions, angle functions or goniometric functions) are real functions which relate an angle of a rightangled triangle to ratios of two side lengths They are widely used in all sciences that are related to geometry, such as navigation, solid mechanics, celestial mechanics, geodesy, and many others Start with the well known pythagorean identity sin2x cos2x ≡ 1 This is readily derived directly from the definition of the basic trigonometric functions sin and cos and Pythagoras's Theorem Divide both side by cos2x and we get sin2x cos2x cos2x cos2x ≡ 1 cos2x ∴ tan2x 1 ≡ sec2x ∴ tan2x ≡ sec2x − 1

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We can represent arctan(2x) with a power series by representing its derivative as a power series and then integrating that series You have to admit this is pretty neatSolve for x tan(2x)= square root of 3 Take the inverse tangent of both sides of the equation to extract from inside the tangent The exact value of is Divide each term by and simplify The tangent function is negative in the second and fourth quadrants To find the second solution,Answered 2 years ago tan (x) is an odd function which is symmetric about its origin tan (2x) is a doubleangle trigonometric identity which takes the form of the ratio of sin (2x) to cos (2x) sin (2x) = 2 sin (x) cos (x) cos (2x) = (cos (x))^2 – (sin (x))^2 = 1 – 2 (sin (x))^2 = 2 (cos (x))^2 – 1 Proof

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Tan (2x) = 2 tan (x) / (1 tan ^2 (x)) sin ^2 (x) = 1/2 1/2 cos (2x) cos ^2 (x) = 1/2 1/2 cos (2x) sin x sin y = 2 sin ( (x y)/2 ) cos ( (x y)/2 ) cos x cos y = 2 sin ( (x y)/2 ) sin ( (x y)/2 ) Trig Table of Common Angles angle(2 x) d x = ∫ 0 π / 4 tan (2 x) d x ∫ π / 4 π / 2 tan (2 x) d x For the integral to exist, we need existence of both those integralsA special trigonometric function is formed to represent a value in mathematics as x approaches tan − 1 3 x So, try to change the limit value in the same form x → 3 x approaches 3 It is undefined So, the limit of trigonometric function should be solved in another method to obtain value of the function as x approaches tan − 1

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 Answers #1 0 Since the result is 2, it must mean that the opposite side divided by the djacent side equals 2 This only occurs whens the oppostie side is twice the adjacent side Therefore it must be at an angle of 30 degrees If you draw the triangle this can be verified Guest⇒ z = 1 (1 tan x tan y tan x − tan y ) 2 = 1 (1 n tan 2 y n tan y − tan y ) 2 ⇒ z = 1 ( n − 1 ) 2 ( 1 n tan 2 y tan y ) 2 = 1 ( n − 1 ) 2 ( 1 n t 2 t ) 2 by putting t = tan y(x) are non constant continuous and differentiable functions and f(x) is a polynomial of degree 4 with leading coefficient equal to 1, then for at (A) Area of the smaller region bounded by the curve y = f(x)and xº y = 1 is T 2 squnits 4 5 (B) Area included between y = f(x);y 2 = 0 and between ordinates x = 0 and x = 3 is 33 squnits 5 3 Area bounded by the line y = x 1 and y = f(x

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X = cos1 1 1 t 2, y = sin1 1 1 t 2 ⇒ dy dx is equal to 0 tan(t) 1 sin(t) cos(t) C 1 Given, x = cos1 1 1 t 2 and y = sin1 1 1 t 2 👍 Correct answer to the question Which expression is equivalent to sec^2xcot^2x A sin²x B csc²x C (1)/(cos^2x) D (1/(tan^2x) eeduanswerscom Ex 131, 22 lim┬(x → π/2) tan⁡2x/(x − π/2) lim┬(x → π/2) tan⁡2x/(x − π/2) Putting y = x – π/2 When x → 𝜋/2 y → 𝜋/2 – 𝜋/2 y → 0

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